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14x^2+3x=2x+2
We move all terms to the left:
14x^2+3x-(2x+2)=0
We get rid of parentheses
14x^2+3x-2x-2=0
We add all the numbers together, and all the variables
14x^2+x-2=0
a = 14; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·14·(-2)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{113}}{2*14}=\frac{-1-\sqrt{113}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{113}}{2*14}=\frac{-1+\sqrt{113}}{28} $
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